(Decrease in Second Year)/(Decrease in Third year)→ 100/(100-r) = 5/4 400 = 500 - 5r 5r = 100 r = 20% Let the Population of Tigers 3 years ago be P, then P(1-20/100)3= 11520 P(4/5)3= 11520 P= (11520 ×5 ×5 ×5)/(4 ×4 ×4) = 22500
447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
(29.97%) of 9840 + ? + (45.17% of 1240) = (31.955% of 11750)
15.001% of 799.99 - 3/11% of 1099.99 + 111.002 = ?
Find the difference of day had the highest number of books and that of lowest number of books sold?
96.03% of √225.02 × 14.98 = ? + 19.98
4.93% of 539.92-48% of 4700=?-8330.33
`(601/49)xx(399/81)` ÷ `(29/201)` = ?
540.11 ÷ 17.98 × 5.14 – 131.9 = √?
(44.11/4.01) + (11.99/3.03) + 23.9% of 49.978 = ?3.03
108.31% of (4.9/9.012) of ? = 23.9% of 2499.9