If the ratio between two numbers is 3: 5 and their LCM is 120, then the numbers are:
Let the HCF of two numbers = y Let the two numbers be 3y and 5y. => 3y × 5y = 120 × y ⇒ 15y = 120y ⇒ 15y = 120 ⇒ y = 8 3y = 3 × 8 = 24 5y = 5 × 8 = 40 ∴ The two numbers are 24, 40.
I. 2x² - 15x + 13 = 0
II. 3y² - 6y + 3 = 0
I. 99x² + 161 x + 26 = 0
II. 26 y² + 161 y + 99 = 0
I. 35x² + 83x + 36 = 0
II. 42y² + 53y + 15 = 0
I. 18p²- 21p + 6 = 0
II. 16q² - 24q +9 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
I.70x² - 143x + 72 = 0
II. 80 y² - 142y + 63 = 0
I. 2x2 – 19x + 45 = 0
II. y2 – 14y + 48 = 0
I. 3x2 = 2x2 + 9x – 20
II. 3y2 = 75
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
I. 3x2 + 3x - 60 = 0
II. 2y2 - 7y + 5 = 0
