The ratio of A's and B's salary is 6 : 7. If B's salary is increased by 5(1/2)%, then his total salary becomes Rs 1,26,600. The salary (in Rs) of A is:
Let A's salary = 6x and B's salary = 7x A's salary increased by 11.5% = 6x × (11/2)% ⇒ 3x × (11/100) ⇒ 3x ×0 .11 ⇒ o.33x According to question 6x + 0.33x = 126600 ⇒ 6.33x = 126600 ⇒ x = 20,000 B's salary = 7 × 20,000 ⇒ Rs. 1,40,000 ∴ B's salary is RS.1,40,000
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
I. 2y2- 37y + 143 = 0
II. 2x2+ 15x – 143 = 0
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0