Let number of 10 paisa, 20 paisa and 50 paisa coins be ‘8x’, ‘9x’ and ‘10x’, respectively. ATQ, (0.1 × 8x) + (0.2 × 9x) + (0.5 × 10x) = 38 Or, 0.8x + 1.8x + 5x = 38 Or, 7.6x = 38 So, x = 5 So, number of 20 paisa coins = 9x = 45 Therefore, required number of coins = 0.8 × 45 = 36
Five years ago, the average age of a family of four members was 25 years. Six years hence, the ratio of their ages will be 9:7:5:3. Find the a...
Five years ago, the ratio of Aman's age to Rahul's age was 6:5. It is also known that Aman's age will be 47 years five years from now. Additionally, R...
Ratio of present ages of P and Q is 2:5. After two years from now the ratio of ages of P and R will be 5:12. R is one year elder to Q. Find the present ...
7 years ago, Meera’s age was equal to the Heena’s present age. The sum of Meera’s age 10 years from now and Heena’s age 5 years ...
A girl’s age is 155% of what it was 10 years ago, but 55% of what it will be after 10 years. What is her present age?
B is 5 years older than A and A is 8 years older than C. If the sum of the age of A and C is 24 years, then find the sum of the ages of all three.
At present, Rahul and Rajat have ages in a 7:5 ratio. Anirudh age is 3 years less than Rahul and Sneha age is 5 years more than Rajat If the average cur...
A is younger than B by 5 years. If the ratio of A and B ages is 6:7 respectively, then find the age of A.
The ratio of age of A and B after 8 years is 4:5 respectively. The ratio of age of A and C 6 years ago is 3:4 respectively. If the present average age o...
A is five times as old as B. C was twice-as old as A six years ago. In six years' time, A will be 31. Find the sum of the present ages of B and C.
