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Let number of 10 paisa, 20 paisa and 50 paisa coins be ‘8x’, ‘9x’ and ‘10x’, respectively. ATQ, (0.1 × 8x) + (0.2 × 9x) + (0.5 × 10x) = 38 Or, 0.8x + 1.8x + 5x = 38 Or, 7.6x = 38 So, x = 5 So, number of 20 paisa coins = 9x = 45 Therefore, required number of coins = 0.8 × 45 = 36
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