Let number of 10 paisa, 20 paisa and 50 paisa coins be ‘5x’, ‘8x’ and ‘7x’, respectively. ATQ, (0.1 × 5x) + (0.2 × 8x) + (0.5 × 7x) = 35 Or, 0.5x + 1.6x + 3.5x = 35 Or, 5.6x = 35 So, x = 6.25 So, number of 20 paisa coins = 8x = 50 Therefore, required number of coins = 0.40 × 50 = 20
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