Start learning 50% faster. Sign in now
Let the total quantity of mixture in vessel A and B respectively 9a and 20a litres. Quantity of milk in vessel A = 9a x 11/20 = 4.95a Quantity of milk in vessel B = 20a x 13/50 = 5.20a Now, (5.20a – 4.95a) = 12 So value of a = 12/0.25 = 48 Total quantity of mixture in vessel A = 48 x 9 = 432 litres Total quantity of mixture in vessel B = 20 x 48 = 960 litres Total quantity of milk in vessel C = 432 x 11/20 + 960 x 13/50 = 237.6 + 249.6 = 487.20 litres Amount of milk left in vessel C after removal of 25% mixture from vessel C = 75% of 487.20 = 365.40 litres Hence answer is option B
The Saubhagya Scheme aims to achieve which of the following?
Which city hosted the 32nd International Conference of Agricultural Economists (ICAE 2024) in August 2024?
Who was the founder of Tasvir Khana?
Consider the following statements:
I. For comprehensive rehabilitation of persons engaged in begging in 75 identified municipalities the Social J...
Which renowned wildlife sanctuary in Uttar Pradesh is known for its population of swamp deer (Barasingha)?
The Global Spirituality Festival 2024 will be organized from March 14-17 at the world's largest meditation centre, Kanha Shanti Vanam, ___.
How many countries from the Global South are part of the Voice of Global South initiative?
DipaKarmakar, who recently announced her retirement, was associated with which sports?