Question
There are three series given below which are following
with the same pattern. Series I: 9, 10, 32, 163, 1145 Series II: 4, B, C, D, E Series III: F, G, H, I, J Also, G = 3C + 5, Find the product of F & H.Solution
Series I: 9 × 1 + 1 = 10 10 × 3 + 2 = 32 32 × 5 + 3 = 163 163 × 7 + 4 = 1145 Series II: 4 × 1 + 1 = 5 (B) 5 × 3 + 2 = 17 (C) 17 × 5 + 3 = 88 (D) 88 × 7 + 4 = 620 (E) Series III: F × 1 + 1 = G G × 3 + 2 = H H × 5 + 3 = I I × 7 + 4 = J And, G = 3C + 5 G = (3 × 17) + 5 G = 56 Now we can find the value of F, F × 1 + 1 = G F × 1 + 1 = 56 F = 55 Also, we can find the value of H, G × 3 + 2 = H 56 × 3 + 2 = H H = 170 The product of F & H = (55 × 170) = 9350
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