Question
Given below are 3 numbers series I, II and III with an
odd one out number (wrong number) in each of the series. The number that should actually come in place of the wrong number in respective series respectively are P, Q and R respectively. On this basis, establish the correct relationship between P and Q and between Q and R respectively I. 30, 58, 116, 222, 439, 872 II. 71, 104, 73, 416, 335, 1666 III. 126, 138, 114, 150, 92, 162Solution
For series I: 30 × 2 - 2 = 58 58 × 2 - 3 = 113 113 × 2 - 4 = 222 222 × 2 - 5 = 439 439 × 2 - 6 = 872 So, P = 113 For series II: 71 + 33 = 98 98 - 52 = 73 73 + 73 = 416 416 - 92 = 335 335 + 113 = 1666 So, Q = 98 For series III: 126 + (12 × 1) = 138 138 - (12 × 2) = 114 114 + (12 × 3) = 150 150 - (12 × 4) = 102 102 + (12 × 5) = 162 So, R = 102 And so, P > Q and Q < R
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