Question

Given below are three series I, II and III. Each series

Q: Answer- Given below are three series I, II and III. Each series consist an odd one out number. Odd one out...

For series I 20 5 - 5 95 95 4 - 4 376 376 3 - 3 1125 1065 2 - 2 2248 So, P 100 For series II 224 - 22 220 220 - 52 195 195 - 82 131 131 - 112 10 10 - 142 -186 So, Q 128 For series III 2083 0.5 1043 1043 1 1043 1043 1.5 52 52 2 104 104 X 2.5 260 So, R 108 Therefore, P Q and Q R

consist an odd one out number. Odd one out number in series I, II and III are 'P', 'Q' and 'R', respectively. You have to find the values of 'P','Q' and 'R' and establish a relation among them. I. 20, 100, 356, 1065, 2128 II. 224, 220, 195, 128, 10, -186 III. (208/3), (104/3), (104/3), 52, 108, 260

A P = Q, Q > R

B P < Q, Q > R

C P = Q = R

D P > Q, Q > R

E P < Q, Q < R