Question
Three series are given below. You have to find the
values of P, Q and R, then establish a relationship among them. I: 840, P , 584, 456, 520, 488 II: 750, 21, 264, ( P/2 + 19), 210, Q III: 225, 250, Q , 282, 161, RSolution
ATQ, Series (i), 840 – 29 = 328 328 + 28 = 584 584 – 27 = 456 456 + 26 = 520 520 – 25 = 488 P = 328 Series (ii), (P/2) + 19 = (328/2) + 19 = 164 + 19 = 183 750 – 36 = 21 21 + 35 = 264 264 – 34 = 183 183 + 33 = 210 210 – 32 = 201 Q = 201 Series (iii), 225 + 52 = 250 250 – 72= 201 201 + 92 = 282 282 – 112 = 161 161 + 132 = 330 R = 330 Thus, R > P > Q.
20% of 10% of 900 + 84/12 = ?2
32 of (16/8) of (30/24) of (120/x) = 30
√256 * 3 – 15% of 300 + ? = 150% of 160
If the weight of 1 liter of water is 1 kilogram, then the volume of 0.1 gram of water is how many cubic millimeters.
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
360 ÷ 9 + 15 % of 200 + ? * 10 = 45 * √25
?² = 37% of 800 – 14 × 18+ 5! - 20
690 ÷ (75% of 460) = ? ÷ (50% of 160)
(√7225 x √1225)/(√625) = ?
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