Question
Below given are 2 wrong number series. Series I:
19, 30, 6, 45, – 11, 67 Series II: 141, 148, 223, 398, 723, 1248 I. The absolute difference between the incorrect numbers is divisible by 37. II. The sum of the incorrect numbers is divisible by 13. III. When 'x' is divided by 'y', the remainder is 15, where 'x' represents the correct replacement for the wrong term in series I, and 'y' represents the correct replacement for the wrong term in series II.Solution
ATQ, Series 1 19 + 11 × 1 = 30 30 – 12 × 2 = 6 6 + 13 × 3 = 45 45 – 14 × 4 = – 11 – 11 + 15 × 5 = 64 x = 64 Series 2 {148 – 123 = 25} 75 – 25 = 50 {223 – 148 = 75} 175 – 75 = 100 {398– 223 = 175} 325 – 175 = 150 {723 – 398 = 325} 525 – 325 = 200 1248 – 723 = 525 y = 123 I.141 – 67 = 74 = 2 × 37 (True) II.141 + 67 = 208 = 208/13 = 16 (True) III.64/123 = (False) Hence, Only I and II
17   9   10   16.5   35    ?    273
27 28 32 41 57 ?
...Find the missing number in the given number series.
3, 7, 18, 38, 69, ?14, 34, 19, 29, 24, ? , 29, 19
5 6 14 45 ? 925
...98, 89, 114, 50, 194, ?
What will come in the place of questions (?) mark in the following questions.
160, 223, 271, 306, 330, ?
What will come in place of the question mark (?) in the following series?
16, ?, 480, 1920, 5760, 115205, 5, 15, 75, ?, 4725
What will come in place of the question mark (?) in the following series?
10, 410, ?, 710, 760, 785
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