If the simple interest on a certain sum of money for 15 months at 3(1/2)% per annum exceeds the simple interest on the same sum for 9 months at 2(1/2)% per annum by Rs. 25.25. Find the sum.
Let the sum be Rs x. Then, => ((x× 7× 15× 1)/(2× 12× 100)) - ((x× 5× 9× 1)/(2× 12× 100)) = 25.25 => (7x)/160 - (3x)/160 = 25.25 => x = (25.25× 160)/4 = Rs 1010
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