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We have the formula: Difference = (PR2 (300 + R))/(100)3 66.56 = (P× (20)2× (300 + 20))/(100)3 P = (66.56× 100× 100× 100)/(20× 20× 320) P = Rs. 520
A certain sum of money becomes Rs. 1500 in 1 year and 2800 in 3 years at certain rate of simple interest. Find the sum of money invested.
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The savings of Arun and Bhaskar are same. The difference between the expenditure of Bhaskar and the savings of both Arun and Bhaskar together is 0. The ...
A sum of Rs. 4000 is invested at simple interest for 2 years. If the rate interest for first year is 15% p.a. while 25% p.a. for second year, then find ...
