A certain sum of money becomes 3 times of itself in 10 years at simple interest. In how many years does it become double of itself at the same rate of simple interest?
Let the principal = Rs. x, Amount = Rs. 3x, Time = 10 years ∴ Simple Interest = Rs. (3x – x) = Rs. 2x Rate = [(2x × 100)/(x × 10)]% p.a. = 20% p.a. Now, Principal = Rs. x, Amount = Rs.2x, Rate = 20%p.a. Simple Interest= Rs. (2x − x)= Rs. x ∴ Time =(x × 100)/(x × 20) = 5 years.
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
63- [22-{24 ÷ 3-(9-15 ÷ 5) ÷ 6}]=?
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
(〖(0.4)〗^(1/3) × 〖(1/64)〗^(1/4) × 〖16〗^(1/6) × 〖(0.256)〗^(2/3))/(〖(0.16)〗^(2/3) × 4^(-1/2) ×〖1024〗^(-1/4) ) = ?
(3500 ÷ √1225) × √(20.25) = ? ÷ 4
√ 225 x 24 - √ 144 x 18 = ?
[123 ÷ 8 ÷ 9] × 144 = ? + 12 × 5
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608
2/5 of 3/4 of 7/9 of 14400 = ?
(√196 + √121) × 4 = ?/2
