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Let the principal = Rs. x, Amount = Rs. 3x, Time = 10 years ∴ Simple Interest = Rs. (3x – x) = Rs. 2x Rate = [(2x × 100)/(x × 10)]% p.a. = 20% p.a. Now, Principal = Rs. x, Amount = Rs.2x, Rate = 20%p.a. Simple Interest= Rs. (2x − x)= Rs. x ∴ Time =(x × 100)/(x × 20) = 5 years.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 2x² - 8x + 6 = 0
Equation 2: y² - 7y + 10 = 0
I. 35x² - 51x + 18 = 0
II. 30y² + 17y – 21 = 0
I. x² - 208 = 233
II. y² + 47 - 371 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. x + 1 = 3√ 9261
II. y + 1 = √ 324
I: √(100 x4 + 125x4) + 7x + 41/2 = -4x
II: 3√(64y3) x 2y + 19y + 72 = -3y +...
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I. 4x² - 15x + 9 = 0
II. 20y² - 23y + 6 = 0
I. x² + 4x + 4 = 0
II. y² - 8y + 16 = 0