1000 rupees is invested in a scheme p.a. simple interest. Another amount (1000 – x) is invested in scheme B at 2R% p.a. simple interest. After 5 years, interest earned from scheme A is 20% less than that of scheme B. Find x.
Interest earned from scheme A = (1000 × R × 5)/100 = 50R Interest earned from scheme B = ((1000 – x) × 2R × 5)/100 = R(1000 – x)/10 According to the question, => 50 R = 4/5 × R(1000 – x)/10 => 1000 – x = 625 => x = Rs. 375
√10201 × √3969 - (52)² = √? + (60)²
...1090 + 237 + 30549 - 86 - 104 = ? x 6
4567.89 - 567.89 - 678.89 = ?
(? × 3)2 - 85 = 115 × 5 + 69
181/8 + 51/4 – 63/8 = ? + 9/2
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
(750 / 15 × 15 + 152 + 20% of 125) = ?3
(1748 ÷ 8) + 76.8 × 35 =(? × 4) + (42 × 35.5)
((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
