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CI = P [(1 + (R/100)n) – 1] => CI = x [(1 + (20/100)2) – 1] => CI = x [(36/25) – 1] => CI = 11x/25 Now, interest received was reinvested in scheme B. SI = (11x × 15 × 2)/(25 × 100) => SI = 33x/250 Amount = P + SI => 1430 = 11x/25 + 33x/250 => x = Rs.2500 Alternate Method: => (130/100) × 0.44x = 1430 => x = Rs.2500
If x 2 – 15x + 51 = 0, then determine the value of (x – 5) + {1/(x – 5)}.
√(92×8 ×52+700) = ?
{(21/20) + (20/21)}2 - {(21/20) - (20/21)}2 = ?
In a college, the proportion of boys to girls is 7:9, and the proportion of graduate students to postgraduate students is 4:5. Determine the total numbe...
The average of three numbers a, b and c is 2 more than c. The average of a and b is 48. If d is 10 less than c, then the average of c and d is:
If a3 + b3 = 6240 and a + b = 30, then find the value of {(a + b)2 – 3ab}
If 15a2 + 1 = 20a, then find the value of {(9a2 + 1)/25a2}
1/3 + 1/15 + 1/35 + 1/63 + 1/99 = ?
In a class of 70 students and 25 teachers, each student got gifts that were 20% of total number of students and each teacher got gifts that were 10% of ...
