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CI = P [(1 + (R/100)n) – 1] => CI = x [(1 + (20/100)2) – 1] => CI = x [(36/25) – 1] => CI = 11x/25 Now, interest received was reinvested in scheme B. SI = (11x × 15 × 2)/(25 × 100) => SI = 33x/250 Amount = P + SI => 1430 = 11x/25 + 33x/250 => x = Rs.2500 Alternate Method: => (130/100) × 0.44x = 1430 => x = Rs.2500
There are five persons with different heights. D is shorter than R. J is taller than L. U is shorter than J but taller than R. R is not taller than L. W...
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Who among the following got the lowest marks?
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Who among the following is the third lightest person?
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If box R has 8 shirts and box P has 4 times the number of shirts of box R then what is the possible number of shirts in box T?
Five friends F, G, H, I and J have different heights but not necessarily in the same order. F is taller than G. J is taller than I, who is taller than G...
If the box S has 32 shirts, then what will be the possible number of shirts of P?