A certain sum of money invested at R% p.a. fetches a compound interest (compounded annually) of 1525.5 and simple interest of Rs.1500 at the end of 2 years. Find the value of ‘R’.
Difference between compound interest and simple interest for 2 years = 1525.5 – 1500 = Rs.25.5 Simple interest for 1 year = 1500/2 = Rs.750 So, R = (25.5/750) × 100 = 3.4%
(?)2 + 4.113 = 23.92 – 28.03
(124.99)² = ?
³√? `xx` 32.87 + 59.83 `xx` 28.7665 – 48.8745 `xx` 21.642 = 1085.344
2720.03 ÷ 79.98 x 39.9 = ? + 40.32
? + 144.99 – 120.01 = 25.01 × 6.98
(108.999)² - (102.001)²=?
6940 ÷ 28 ÷ 7 = ?
`[(sqrt(750) xx15.981) -: 54.003]` `xx` ? = 6997.81001
(88.931% of 435) + (61.521% of 516) = ?
`5(17/23)` + `1(15/46)` - `5(17/25)` = ? - `6(13/23)`
