Question
Suresh earned an interest of Rs. 1677 on principal
amount of Rs. 5200 at some rate of compound interest in 2 years. How much more/less interest would he have earned on Rs. 5700 at the same rate of simple interest for the same duration?Solution
Let, rate of interest be ‘r’% per annum So, 1677 = 5200 × {(1 + r/100)2 – 1} 129/400 = {(1 + r/100)2 – 1} 529/400 = (1 + r/100)2 (23/20)2 = (1 + r/100)2 23/20 = 1 + r/100 3/20 = r/100, r = 15 So, simple interest earned = 5700 × 0.15 × 2 = Rs. 1710 Required amount = 1710 – 1677 = Rs. 33
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
I. 2p2 + 5p + 2 = 0Â Â Â Â Â Â Â Â II. 2q2 + 11 q + 14 = 0
For which value of m, there is no solution to the equation -
a – b = 5
ma – 4b = 1
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
The ratio of roots of an equation
ax²+bx+b = 0 is p : q
Then find, √p/√q + √q/√p + √p/√q ?
The slope of the equation 24x+ 8y =56 is
If, x - y radic; 3 = 23 and radic; 3x + y = 35
Find the angle between both the lines when they intersect each other.
...I. p2 – 5p + 6 = 0                 Â
II. 36q2 = 81
...Solve for x: 5x − 7 = 3x + 9
A line passes through the points (2, 3) and (5, −3). Find its equation.
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