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Let, rate of interest be ‘r’% per annum So, 1032 = 3200 × {(1 + r/100)2 – 1} 129/400 = {(1 + r/100)2 – 1} 529/400 = (1 + r/100)2 (23/20)2 = (1 + r/100)2 23/20 = 1 + r/100 3/20 = r/100, r = 15 So, simple interest earned = 3600 × 0.15 × 2 = Rs. 1080 Required amount = 1080 – 1032 = Rs. 48
(43/10) + (4.2/1.2) - (2.7/3) = (?/4) + (2.7/6.0)
4261 + 8234 + 2913 + 8217 + 6283 + 4172 =?
(64/25)? × (125/512)?-1 = 5/8
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
? (1/2) = 236 – 25 × 18/2 + 396 ÷ 22
0.25 x 696 ÷ 0.3 = ?
7/11 × 1034 + 1(4/7) × 2401 = 1230 +?
60% of 3050 + 80% of 6050 =?
2(3/4) of 2880 + 54% of 7520 - ? = 302