A man deposited 25% of his salary to a bank which offers compound interest at the rate of 10% p.a. If the interest earned by him from the bank after 2 years is Rs. 3780, find the monthly expenditure of the man which is 56% of his monthly salary.
Let the amount of money deposited in the bank be Rs. ‘x’. So, x × [(1.1)2 – 1] = 3780 0.21x = 3780, x = 18000 So, monthly income of man = 18000/0.25 = Rs. 72000 Required monthly expenditure of man = 56% of 72000 = Rs. 40320
9999² + 1111² =?
641.5 + 72 × 8 = ? × 4
72 + 122 - 25% of 600 = ?
∛157464 =?
6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
(49 x ?) / 3.5 + 389 = 627
2850 ÷ 2.5 - ? × 42 = 300
135.37 – 50.24 + 629.09 – 199.50 = ? – 214.68 + 42.65
1885 ÷ 64.98 + 7.29 + ? = 69.09
? ÷ 8 = 2048 ÷ 64
