Question
The difference between compound interest and simple
interest at rate of 16% per annum for 2 years is Rs. 192. Find the simple interest obtained on same amount for a period of 2 years at rate of 10% per annum.Solution
Let, the amount be Rs. P. P[(1 + 16/100)2 – 1] – P × 16% × 2 = 192 P × 0.3456 – P × 0.32 = 192 P × 0.0256 = 192 P = 192 ÷ 0.0256 = Rs. 7500 Therefore, required interest = 7500 × 10% × 2 = Rs. 1500
More Simple and compound interest Questions
If sin(x + y) = 1 and sin(x - y) = (1/2), then what is the value of sinx cosx + 2sin2y + cos2y?Â
Simplify (cos13°+sin 13°) /(cos13°-sin13°)
If Sin 3A = Cos (A - 46°) where 3A is acute angle, then the Value of A is
Evaluate 3sin x – 4 sin3 x and figure out the correct answer from below option ?
If sin(x + y) = 3/5 and cos(x - y) = 12/13, where x, y ∈ [0, π/2], find sin(2x) + sin(2y).
Find the value of sin 240 °
What is the value of [tan2 (90 – θ) – sin2 (90 – θ)] cosec2 (90 – θ) cot2 (90 – θ)?
...- sin1440° - cot630° - sin120°cos150° is equal to:
Relevant for Exams:
