The difference between compound interest and simple interest at rate of 20% per annum for 2 years is Rs. 240. Find the simple interest obtained on same amount for a period of 2 years at rate of 10% per annum.
Let, the amount be Rs. P. P[(1 + 20/100)2 – 1] – P × 20% × 2 = 240 P × 0.44 – P × 0.4 = 240 P × 0.004 = 240 P = 240 ÷ 0.004 = Rs. 6000 Therefore, required interest = 6000 × 10% × 2 = Rs. 1200
345 = √2704 ÷ (?% of 104) + 7 3
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
7.4 × 8.2 + 3.5 × 4.5 = ? + 11.5 × 2.5
(8 x 9) ÷ 5 + ?2 = 23.4
6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...60% of 250 + 14 × 10 - 210 = ?
√(?) ² = √7396 - √6889
182 – 517 ÷ 11 - √361 = ?
1120 / √x = 80 Then x = ?
