Question
The difference between compound interest and simple
interest at rate of 22% per annum for 2 years is Rs. 484. Find the simple interest obtained on same amount for a period of 2 years at rate of 10% per annum.Solution
Let, the amount be Rs. P. P[(1 + 22/100)2 – 1] – P × 22% × 2 = 484 P × 0.4884 – P × 0.44 = 484 P × 0.0484 = 484 P = 484 ÷ 0.0484 = Rs. 10000 Therefore, required interest = 10000 × 10% × 2 = Rs. 2000
The present age of A is 7/5 times to that of his marriage age. Present age of his brother is 1/2nd of his present age. If A was married 20 years ago the...
The present age of ‘T’ is 36 years, which is 50% more than that of ‘U’. The average of present ages of ‘U’ and ‘V’ is 42 years. The pres...
Present ages of P and Q are in the ratio 4:9 respectively. If Q’s age, 12 years hence from now will be 4 times of P’s age, 4 years ago from now, the...
The average age of a group of 40 people is 22 years. If the age of 5 people is excluded, the average age decreases by 1 year. What is the average age of...
Present ages of ‘A’, ‘B’ and ‘C’ are in the ratio 10:12:15, respectively. If present average age of ‘A’ and ‘C’ is 50 years, then fi...
The ratio of the present ages of Ginni and Binni is 9:4 respectively. Ginni is ‘n’ years older than Binni. If after 5 years, the ratio of the ages o...
A’s age is 180% of what he was 5 years ago, But 90% of what it will be after 5 years. What is his present age?
5years ago, the ages of 'Arunita' and 'Bhasker' were in the ratio 2:3. 5years from now, the age of 'Arunita' will be 25% less than that of 'Bhasker'. De...
The sum of ages of 4 children born at the intervals of 2 years each is 36 years. Find out the age of the youngest child.
Present age of ‘A’ is 60% more than that of ‘B’. If 13 years hence from now, ‘B’ will be 12 years younger than ‘A’, then find the sum of...
Relevant for Exams:
