A man deposited Rs. ‘x + 1400’ at 12% per annum simple interest and earned Rs. 828 as interest after 2 years. Find the interest earned by him if he deposited Rs. 2x at 10% per annum for 2 years at compound interest.
So, {(x + 1400) × 0.12 × 2 = 828 0.24x + 336 = 828 x = 492/0.24 = 2050 So, required interest earned = 2 × 2050 × 0.21 = Rs. 861
(462.23 × 127.84 ÷ 153.88) ÷ √(31.98 × 7.92) = ? ÷ 15.15
180.25 × 14.995 ÷ √26 = ? × 5.985
(1280.23 ÷ 31.98) + (912.32 ÷ 23.9) + 1864.11 = ?
√ 27556.11 × √ 624.9 – (22.02) 2 =? × 5.95
`sqrt(1279.98+sqrt(243.97+sqrt(140.22+sqrt(6.875+sqrt(76.09+sqrt(24.97)))))) = ? `
(5.013 – 30.04) = ? + 11.98% of 4799.98
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
√323.89 × (3.20) ÷ 9.02 =?
416.021÷ 3.782 + 13.012× 24.987 =?
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