Rs. 5000 when invested at simple interest of r% p.a. amounts to Rs. 6000 in 24 months. If the same sum had been invested for 1 year at compound interest of (r + 32) % p.a. (compounded in every 4 months), then the amount received would be?
According to the question, 6000 – 5000 = (5000 × r × 24) ÷ (12 × 100) Or, 1000 = 100 × r Or, r = 10 When the sum is invested at compound interest, Effective rate of interest = (r + 32) ÷ 3 = (10 + 32) ÷ 3 = 14% Effective time period = 1 × 3 = 3 units Amount received = Principal × {1 + (r/100)}time period = 5000 × {1 + (14/100)}3 = 5000 × (1.14)3 = 7407.72
The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠ -1) has equal roots. find the value of p.
I. y/16 = 4/y
II. x3= (2 ÷ 50) × (2500 ÷ 50) × 42× (192 ÷ 12)
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ is
...(i) 2x² – 9x + 10 = 0
(ii) 4y² – 12y + 9 = 0
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 6y2- 17y + 12 = 0
II. 15x2- 38x + 24 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
