Question
Sunil invested Rs. β4xβ in scheme βAβ offering
simple interest of 25% p.a. and reinvested the interest earned from scheme βAβ at the end of 4 years in scheme βBβ offering compound interest of 20% p.a. compounded annually. If total amount received from scheme βBβ after 2 years is Rs. 4320, then find the value of β12xβ.Solution
According to question; 1.44 Γ {0.25 Γ 4 Γ 4x} = 4320 Or, {0.25 Γ 4 Γ 4x} = 3000 Or, x = 750 So, 12x = 12 Γ 750 = 9000
12(3/5) + 4(1/5) × 3(2/3) =?
1.25 Γ 36 + 2.75 Γ 40 = ? Γ 3.1
1*1/2 + 11*1/3 + 111*1/2 + 1111*1/3 + 11111*1/3 =?
- What will come in the place of question mark (?) in the given expression?
?Β² = 28% of 35% of 4500 What will come in the place of question mark (?) in the given expression?
[{(24) 2 Γ· (6) 2 } Γ· 8]4 = ? Γ· 5

If 28957.5 Γ· 268.125= 108, then 289.575 Γ· 2681.25 is equal to:
β(24 Γ 5 Γ· ?) Γ 4 = 56 + 34 β 10
Simplify the following expression:
Β Β (400 +175) Β² - (400 β 175) Β² / (400 Γ 175)