Sunil invested Rs. ‘4x’ in scheme ‘A’ offering simple interest of 25% p.a. and reinvested the interest earned from scheme ‘A’ at the end of 4 years in scheme ‘B’ offering compound interest of 20% p.a. compounded annually. If total amount received from scheme ‘B’ after 2 years is Rs. 4320, then find the value of ‘12x’.
According to question; 1.44 × {0.25 × 4 × 4x} = 4320 Or, {0.25 × 4 × 4x} = 3000 Or, x = 750 So, 12x = 12 × 750 = 9000
(462.23 × 127.84 ÷ 153.88) ÷ √(31.98 × 7.92) = ? ÷ 15.15
180.25 × 14.995 ÷ √26 = ? × 5.985
(1280.23 ÷ 31.98) + (912.32 ÷ 23.9) + 1864.11 = ?
√ 27556.11 × √ 624.9 – (22.02) 2 =? × 5.95
`sqrt(1279.98+sqrt(243.97+sqrt(140.22+sqrt(6.875+sqrt(76.09+sqrt(24.97)))))) = ? `
(5.013 – 30.04) = ? + 11.98% of 4799.98
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
√323.89 × (3.20) ÷ 9.02 =?
416.021÷ 3.782 + 13.012× 24.987 =?
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