Question
A man invested Rs. 30,000 at simple interest of 'x%'
p.a. and received Rs. 45,000 after 2 years. If he had invested Rs. 30,000 at simple interest of 'x%' p.a. for 3 years, then find the interest earned by him from this investmentSolution
Total interest earned in 2 years = 45000 - 30000 = Rs. 15,000 ATQ; 15000 = (30000 × x × 2) ÷ 100 Or, x = 25 So, required interest earned = (30,000 × 25 × 3) ÷ 100 = Rs. 22500
If for non-zero x, x² - 4x - 1 = 0, what is the value of x² + 1/x²?
If, ( a + b = 14 ) and ( a² + b² = 106 ), then find the value of (a³ + b³).
If x2 – 10x + 20 = 0, then find the value of (x – 3)2 + 1/(x – 3)2
If x + 1/x = 5 then find out the value of x⁵ + 1/(x⁵)?
What is the value of (a² + b²+4c²- ab-2bc-2ca) (a + b+2c):
(a+2 )² + (b-5)² + (c+3)² = 0
Find the value of √ (a + b + c) ?
...x = 7 - 4√3 then the value of x³+1/x³ is equal to?
If 2x + y = 10 and 3x - 2y = 5, find the value of x + y.
If ab = -15 and (a2 + b2) = 34, then find the value of (a – b).
If x, y, z are the three factors of a 3– 7a – 6, then value of x + y + z will be
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