Let the certain sum of money be Rs.P. So, P x 0.125 x 3 = 2100 => P = Rs.5600 Desired interest = [(1.1)2 – 1] x 5600 = Rs.1176
35 × 540 ÷ 18 of 15 – ? = 15
25.6% of 250 + √? = 119
√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?
(6630 ÷ 13 + 6120 ÷ 12) ÷ (17 × 3) = ?
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
236.23 - 653.23 + 696.23 = ?
36895 - 4256 - 2233 = ?
√64 of √225 = √(25 + ?) X 12
19 × ? = 361 ÷ 19