Given – r =10%, t=3year, A =1331 Let the invested sum =100 The interest of the first year at the rate of 10%=100×10/100=10 1st year10 2nd year101 3rd year10110.1 Total amount =10+10+10+1+1+1+0.1=33.1 ATQ- 33.1=1331 1=10 And now 100=10×100=1000 CI=1331-1000=331 SI=300 The CI-SI =331-300=31.
8, 7, 12, 35, 128, 635
62, 79, 98, 119, 142, 165
975, 1050, 1125, 1200, 1275, 1325
174 180 198 252 414 910
7, 15, 31, 79, 271, 1221
Direction: Find the wrong number in given number series.
3216, 3255, 3320, 3411, 3538, 3671
63, 124, 215, 345, 511, 728
186, 179, 170, 162, 146, 131, 114
105 112 133 168 216 280 357
...10, 14, 30, 64, 130, 230
