A man wants to invest Rs. 60660 in bank accounts of his two sons whose ages are 12 years and 16 years in such a way that they will get equal amount at an age of 120 years @ 33(1/3)% per annum compounded annually. Find the share of elder son?
A = [P(1+ r/100)]n , 33(1/3)% = 1/3 Let the Principal for younger son be x. And the Principal for elder son be y. Now, Interest to be calculated for, Younger son = (120-12) = 108 years Elder son = (120-16) = 104 years Since Amount will be equally distributed then, [x(1+ 1/3)]108= [y(1+1/3)]104 [x (4/3)]108= [y (4/3)]104 y/x = [(4/3)](108 - 104) y/x = 256/81 Elder son’s share = (256/337) × 60660 = 46080
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
63- [22-{24 ÷ 3-(9-15 ÷ 5) ÷ 6}]=?
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
(〖(0.4)〗^(1/3) × 〖(1/64)〗^(1/4) × 〖16〗^(1/6) × 〖(0.256)〗^(2/3))/(〖(0.16)〗^(2/3) × 4^(-1/2) ×〖1024〗^(-1/4) ) = ?
(3500 ÷ √1225) × √(20.25) = ? ÷ 4
√ 225 x 24 - √ 144 x 18 = ?
[123 ÷ 8 ÷ 9] × 144 = ? + 12 × 5
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608
2/5 of 3/4 of 7/9 of 14400 = ?
(√196 + √121) × 4 = ?/2