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ATQ, Let the sum invested in two schemes be Rs. 'P'. Let the rate of interest be 'r%', per annum. We know that, simple interest received at the end of each year of investment is equal. Simple interest received at the end of first year = Simple interest received at the end of second year = (2400/2) = Rs. 1200 Also, simple interest and compound interest received at the end of first year are equal. So, simple interest received at the end of first year = Compound interest received at the end of first year = Rs. 1200 Compound interest received in the second year = 2640 - 1200 = Rs. 1440 So, we can say that a sum of Rs. 1200 amounts to Rs. 1440 at the end of a year at the given rate of interest. Compound interest received for 1 year = Simple interest received for 1 year Simple interest = Principal X (Rate/100) X Time 1200 X (r/100) X 1 = 1440 - 1200 So, r = 240 X (5/24) = 10 Therefore, rate of interest = r = 20%
Find the approximate value of Question mark(?) for given equation.
(71.92% of 149.99) ÷ 12.04 + 107.98 = ?
12.99% of 499.99 ÷ 13.17 = ? ÷ 20.15
(2310.23 ÷ 32.98) + (1008.32 ÷ 23.9) + 1594.11 = ?
?% of 549.83 – 18.05 × 31.96 = 44.94% of 479.84 – 13.98 × 33.13
19.87% of (49.68 × ?) = 19.78% of 1099.87
A can complete a piece of work in 15 days. B is 30% more efficient than A. If they work together, how many days will it take to complete the work?
30.11% of 149.99 + √195.97 ÷ 7.02 = ?
1560.182 ÷ √168 + √143 * √224 – 4649.87 ÷ 30.883= ?
(3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125