Question
Ravi invests Rs. 2,000 on simple interest at 'a%' p.a.
for 4 years and earned an interest of Rs. 800. His friend Vinay invests Rs. 4,800 on simple interest at 30% p.a. for 'b' months and earned an interest of Rs. 3,600. Find the product of 'a' and 'b'.Solution
Simple interest = (Principal × rate × time) ÷ 100 ATQ, 800 = 2,000 × a × 4 ÷ 100 Or, 800 = 80a So, 'a' = 10 And, 3,600 = (4,800 × 30 × b) ÷ (12 × 100) ...... (since, time is in months) Or, 3,600 = 120b Or, 'b' = 30 Therefore, the required product = (a × b) = 10 × 30 = 300
(752.09 - 43.04 x 7.94) ÷  16.9 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(462.23 × 127.84 ÷ 153.88) ÷ √(31.98 × 7.92) = ? ÷ 15.15
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
Bijay can complete a task on his own in 40 days, while Ajay can finish the same task in 25 days. If they alternate working on the...
(36.35 × 14.89) ÷ 8.78 = ? – 59.98
√323.89  × (3.20) ÷ 9.02 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(44.79 × 74.21) ÷ (11.862 – 33.12) + 37.48% of ? = 180.23
23.87% of 449.86 + 17.83 of 4.09 = ?
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