Question
Ravi invests Rs. 2,000 on simple interest at 'a%' p.a.
for 4 years and earned an interest of Rs. 800. His friend Vinay invests Rs. 4,800 on simple interest at 30% p.a. for 'b' months and earned an interest of Rs. 3,600. Find the product of 'a' and 'b'.Solution
Simple interest = (Principal × rate × time) ÷ 100 ATQ, 800 = 2,000 × a × 4 ÷ 100 Or, 800 = 80a So, 'a' = 10 And, 3,600 = (4,800 × 30 × b) ÷ (12 × 100) ...... (since, time is in months) Or, 3,600 = 120b Or, 'b' = 30 Therefore, the required product = (a × b) = 10 × 30 = 300
√324 + √576 = ?/ √9
13 X √? + 256 ÷ 4 = 30% of 900 - 50
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) ÷ 15 X ? = 36 X 30
1231 + 1312 + 2113 – 3211 = ?
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?Â
((9.77)0- 〖(0.1)〗(-1))/(〖(6/24 )〗(-1) ×(3/2)3+ 〖((-2)/6)〗(-1) ) = ?
...Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4
What will be the value after simplifying this continued fraction?
Relevant for Exams:
