Invest Rs. 1,800 at an annual compound interest rate of 'R%.' After two years, the interest accrued is Rs. 792. Determine the rate 'R.'
Or, 792 = 1800 × [{1 + (R/100)}2 – 1] Or, [{1 + (R/100)}2 – 1] = (792/1800) Or, (2592/1800) = {1 + (R/100)}2 Or, 1 + (R/100) = 1.2 So, R = 20
[4(2/3) + 5(1/6)] × 45% of 240 = ?
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
Simplify-
x + 3(y + x – 2) – (x + y).
125% of 80 – 6 × 4 = ? × 13 – 54
144 (1/2) × 14 – 28 = 7 × ?
34 × 5 × 2 ÷ 6 + 7 × 5 + 13 = (?)× 6 – 754
15% of 2400 + (√ 484 – √ 256) = ?
375% of 320 - 80% of 40 ÷ √256 = ?
√1444 + √729 – √2116 = ?