A sum of ₹50,000 is deposited with an annual simple interest rate of 40%. Calculate the total amount that will be obtained after a period of 42 months.
Simple interest = (sum x rate of interest x time period in months ÷ (100 x 12) So, simple interest earned = 50000 x 40 x 42 ÷ (100 x 12) = Rs. 70,000 So, amount after 42 months = 50000 + 70000 = Rs. 1,20,000 Hence, option b.
The number of terms needed to get Sn = 0 in the A.P of 63, 60, 57. . . . .
The mean of the sample data = 60 and median = 48. Find the mode of this distribution.
If the standard deviation of a population is 3.5, what would be the population variance?
Amish invested 2500 Rupees in each of these schemes, offering simple interest of 12% per annum. 16% P.A. and 15% PA. respectively. Find the total intere...
In an A.P 41st term is 50, then the sum of 81 terms of that A.P is:
The sum to n terms of the series 1 + 1 + 3 + 1 + 3 + 5 + 1 + 3 + 5 + 7 …………………… is
24, 29, 62, ?, 758, 3791
...3600, 600, 120, 30, 10, ?
21 is divided into three parts which are in arithmetic progression (A.P.) in such a way that the sum of their square is 179. Find the smallest part.
What will be the mode of the following data?
13, 15, 31, 12, 27, 13, 27, 30, 27, 28 and 16
