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Simple interest = (sum x rate of interest x time period in months ÷ (100 x 12) So, simple interest earned = 50000 x 40 x 42 ÷ (100 x 12) = Rs. 70,000 So, amount after 42 months = 50000 + 70000 = Rs. 1,20,000 Hence, option b.
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
I). p2 + 16p + 55 = 0
II). q2 + 9q + 20 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 21x + 110 = 0
Equation 2: y² - 23y + 132 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
Given the product of the roots of the equation is z2 - (b+c)z + (c+61) = 0 is 63 and sum of roots is 16. Find the value of 2b+3c?
I. 3x2 - 14x + 15 = 0
II. 15y2- 34 y + 15 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 6 y² + 11 y – 7= 0
II. 21 x² + 5 x – 6 = 0
I. 165x² + 97x + 10 = 0
II. 117y² - 163y + 56 = 0
I. 2y2+ 13y + 15 = 0
II. 2x2+ 11 x + 12 = 0
