Question
A man invested $4,800 in a scheme offering compound
interest compounded annually. If the difference between the interest earned in the 2nd year and the 1st year is $48, what is the rate of interest?Solution
Let the rate of interest be R% Interest for the 1st year = 4800×R/100 = 48R Interest for the 2nd year = (4800+48R) × R/100 The difference between the 2nd-year interest and 1st-year interest is $48: (4800+48R) ×R/100 − 48R = 48 0.48R² =48 R=10%
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)     Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
236.23 - 653.23 + 696.23 = ?
Simplify the following expressions and choose the correct option.
40% of 360 + 25% of 248 - 30
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7The value of 97 × 103 is _________.
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
? = 20% of 1200 + 256
55.55% of 30000 – 1111 = ? × 1111
30% of 60% of 1800 + 13 × 14 = (? ÷ 75) × 5
