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Let, marks obtained by Roshan and Rahul in quarterly exam be 9x and 8x, respectively. According to question, (9x) × (3/2) + (8x) × (5/4) = 1410 13.5x + 10x = 1410 23.5x = 1410 x = 1410/23.5 x = 60 So, marks obtained by Rahul in half-yearly exam = (8x) × (5/4) = 10 × 60 = 600
Select the correct combination of mathematical signs that can sequentially replace the * signs and balance the given equation.
42 * 7 * 64 * 11 * 6 *4
((67)32 × (67)-18/ ? = (67)⁸
(750 / 15 × 15 + 152 + 20% of 125) = ?3
(180 ÷ 22 ) ÷ (60% of 30) = (? ÷ 2)
√38809 × √3249 – (91)2 = (?)2 + (50)2 – 36
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608
20% of 450 - 15% of 400 = 25% of ?