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    Question

    A vessel contains 120 liters of a mixture of milk and

    water, with 75% of it being milk. If 30 liters of this mixture is replaced by 30 liters of water, what is the new percentage of milk in the mixture?
    A 56.25% Correct Answer Incorrect Answer
    B 60% Correct Answer Incorrect Answer
    C 65.55% Correct Answer Incorrect Answer
    D 70% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Amount of milk in the initial mixture = 75% of 120 liters = 90 liters Amount of water in the initial mixture = 120 - 90 = 30 liters When 30 liters of the mixture is replaced by water, the amount of milk removed = 75% of 30 liters = 22.5 liters So, the remaining milk = 90 - 22.5 = 67.5 liters The total volume of the mixture remains 120 liters, but now the water is 30 liters (original) + 30 liters (added) = 60 liters Percentage of milk in the new mixture = (67.5/120) × 100 = 56.25% ≈ 56%

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