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Let the amount invested at 10% be ₹x, and the amount invested at 15% be ₹15,000 - x. Interest from the first part = (x × 10 × 2) / 100 = 0.2x. Interest from the second part = ((15,000 - x) × 15 × 2) / 100 = 0.3(15,000 - x). Total interest = ₹3,500, so 0.2x + 0.3(15,000 - x) = 3,500 0.2x + 4,500 - 0.3x = 3,500 -0.1x + 4,500 = 3,500 -0.1x = -1,000 x = ₹10,000. Correct option: d
Select the correct combination of mathematical signs that can sequentially replace the * signs and balance the given equation.
42 * 7 * 64 * 11 * 6 *4
((67)32 × (67)-18/ ? = (67)⁸
(750 / 15 × 15 + 152 + 20% of 125) = ?3
(180 ÷ 22 ) ÷ (60% of 30) = (? ÷ 2)
√38809 × √3249 – (91)2 = (?)2 + (50)2 – 36
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608
20% of 450 - 15% of 400 = 25% of ?