Question
A certain amount of money, when invested at an annual
compound interest rate of 'x%' compounded annually, grows to 1.5376 times its original value in 2 years. Determine the value of 'x'.Solution
Let the sum invested be Rs. 'P' ATQ; 1.5376 X P = P X {1 + (x/100)}2 Or, 1.5376 = {1 + (x/100)}2 Or, 1.24 = 1 + (x/100) Or, 124 - 100 = x So, x = 24
(5.08/3.01) of 41.99 - 24.99% of 120.09 = ? - 9.99
A certain sum of money invested at R% p.a. fetches a compound interest (compounded annually) of 1620 and simple interest of Rs.1500 at the end of 2 year...
125.9% ÷ 9.05 x 99.98 = ? - 69.97 × √324.02 ÷ 5.98
What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)<...
What approximate value should come in the place of (?) in the following questions?
3149.21 –1751.73 - ? * 25.25 = 5221.78 – 41...- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
What approximate value will replace the question mark (?) in the following?
? –...
88% of 1620 + 29² = ? + 1482 ÷ 18
784.69 + 86.96 ÷ 29.01 = 40.01 + ? + 367.88
89.87 × 3.21 + 60.32 = ? × (6.89 2 – 19.21)
