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Let the amount invested in scheme A be ₹x. Then, the amount invested in scheme B is ₹50,000 - x. Interest from scheme A (simple interest) = P × R × T / 100 = x × 12 × 1 / 100 = 0.12x. Interest from scheme B (compound interest) = P(1 + R/100)^T - P = (50,000 - x)(1 + 10/100) – (50,000 - x) = (50,000 - x)(1.1) - (50,000 - x) = (50,000 - x) × 0.1. The total interest from both schemes is ₹5,800, so: 0.12x + (50,000 - x) × 0.1 = 5,800. 0.12x + 5,000 - 0.1x = 5,800, 0.02x = 800, x = 800 / 0.02 = ₹40,000. Thus, the amount invested in scheme A is ₹40,000. Correct option: d
171, 86, 87, 132, 266, 668
23, 45, 115, 161, 270, 349
1080, 1058, 1016, 934, 772, 440
112, 222, 440, 872, 1717 , 3424
169, 224, 293, 385, 497, 629
169, 217, 193, 239, 217, 265
32, 50, 82, 124, 180, 252
16, 36, 128, 768, 6144, 61440
1460, 1443, 1430, 1415, 1404, 1395
Find the wrong number in given number series.
2206, 2230, 2278, 2394, 2566, 2950