(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
2/3 × 4/12 × x/10 × 45 × 1/5 = x/6 + 2/5 (2 x)/10  = x/6 + 2/5 x/5 - x/6 = 2/5 (6x-5x)/30 = 2/5 x/6 = 2 ∴x = 12
Man-in-the-middle attack can endanger security of Diffie-Hellman method if two parties are not
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An ADT defines:
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