((0.1)3+ (1.8)3+ (1.1)3- 0.3 ×1.8 ×1.1)/((0.1)2+ (1.8)2+ (1.1)2- (0.18)- (0.11)- (1.8 ×1.1))= ?
a³ + b³ + c³ - 3abc = (a+b+c) (a² + b² + c² -ab –bc -ca) According to the question, (〖(0.1)〗^3+ 〖(1.8)〗^3+ 〖(1.1)〗^3- 0.3 ×1.8 ×1.1)/(〖(0.1)〗^2+ 〖(1.8)〗^2+ 〖(1.1)〗^2- (0.18)- (0.11)- (1.8 ×1.1)) ⇒ ((0.1+1.8+1.1) ((0.1)^2+ (1.8)^2+ (1.1)^2- (0.18)- (0.11)- (1.8 ×1.1)))/(〖(0.1)〗^2+ 〖(1.8)〗^2+ 〖(1.1)〗^2- (0.18)- (0.11)- (1.8 ×1.1)) ⇒ (0.1+1.8+1.1) = 3
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