Question
If x²y² + (1/ (x2y2)) =
83, then the value of xy – 1/xy is:Solution
x²y² + (1/ (x2y2)) = 83 By subtracting 2 from both sides, we get ⇒ x²y² + (1/ (x2y2)) - 2 = 83 - 2 ⇒ (xy - 1/xy)2 = 81 ⇒ (xy - 1/xy) = √81 ∴ (xy - 1/xy) = 9
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