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ATQ, [1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = [(1.45)3 + (0.55)3 + 3 X 1.45 X 0.55 X 2] = [(1.45)3 + (0.55)3 + 3 X 1.45 X 0.55(1.45 + 0.55)] This of the form (a3 + b3 ) + 3ab(a + b), where 'a' = 1.45 and 'b' = 0.55 And, hence, required value = (a + b)3 = (1.45 + 0.55)3 = (2)3 = 8
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