Let a = 1.5, b = 2.7 and c =4.8. = [a× a × a + b × b × b + c × c × c – 3 × a × b× c] / [a × a + b × b + c × c – a × b – b × c – c × a] =[a3+b3+c3-3abc] / [a2+b2+c2-ab-bc-ca] As we know that - a3+b3+c3-3abc =(a+b+c) a2+b2+c2-ab-bc-ca =[(a+b+c) a2+b2+c2-ab-bc-ca]/ a2+b2+c2-ab-bc-ca The term (a2+b2+c2-ab-bc-ca) cancel out and leave. =(a+b+c) =1.5+2.7+4.8 = 9.
Statements: J = S ≤ A = Y > X, W ≥ J > O = B
Conclusion:
I. W ≥ S
II. S > B
III. B < A
3 बजकर 30 मिनट पर घड़ी की मिनट एवं घण्टे की सूई कितने डिग्री का...
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