√ (12+√ (12+√ (12+⋯ ∞ )) y=√(12+y) Squaring on both sides Y2 = 12 + y Y2 - y - 12 = 0 Y2 - 4y + 3y - 12 = 0 y (y - 4) + 3(y - 4) = 0 (y - 4) (y + 3) = 0 Y = 4 or y = - 3 Answer will be 4.
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