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Given, the roots of the equation x² + 2(k - 4)x + 2k = 0 are equal. When roots are equal then b² = 4ac ⇒ [2(k - 4)]² = 4 * 1 * 2k ⇒ 4(k - 4)² = 8k ⇒ k² - 8k + 16 = 2k ⇒ k² - 10k + 16 = 0 ⇒ (k - 2) (k - 8) = 0 ⇒ k = 2, 8
Rs.5400 is divided into two parts such that if one part be invested at 6% and the other at 9%, the annual interest from both the investments is Rs. 435....
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The simple interest on a sum of Rs X in 5 years is (2/5)of the principal. What is the annual rate of interest?
Anjali invested Rs.14000 in a scheme offering compound interest of x% p.a. compounded annually. If at the end of 2 years, interest received by her from ...
Find the compound Interest on Rs. 8,000 @15 % p.a for 2 years 4 month Compounded annually?
A person invested ₹15,000 in two schemes, Scheme A offering 10% per annum simple interest, and Scheme B offering 12% per annum simple interest. If the...
If the difference between the simple interest and compound interest, compounded annually, on Rs. 40,000 at (r + 4)% rate of interest for 2 years is Rs. ...
A certain sum of money becomes Rs. 1500 in 1 year and 2800 in 3 years at certain rate of simple interest. Find the sum of money invested.
Rs. 10000 when invested at simple interest of r% p.a. amounts to Rs. 12000 in 24 months. If the same sum had been invested for 1 year at compound intere...
The difference between compound and simple interest on a sum of money for 2 years at 5% per annum is Rs. 664. The sum is:
