Question
Find the Value of
β(-β3+β(3+8β(7+4β3)))?ΒSolution
β(-β3+β(3+8β(7+4β3) ) )Β Β β(-β3+β(3+8β(4+3+2Γ2Γβ3) ) )Β Β β(-β3+β(3+8β(2Β²+(β3)Β²+2Γ2Γβ3) ) )Β Β β(-β3+β(3+8β((2+β3)Β²)) )Β Β β(-β3+β(3+8(2+β3)))Β Β β(-β3+β(3+16+8β3) )Β Β β(-β3+β(19+8β3) )Β Β β(-β3+β(16+3+2Γ4Γβ3) )Β Β β(-β3+β(4Β²+(β3)Β²+2Γ4Γβ3) )Β Β β(-β3+β((4+β3)Β²))Β Β β(-β3+4+ β3)Β Β = β4 = 2

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1.Β Β Β Β Β Β Null hypothesis H0 : ΞΌ1 = ΞΌ2 = ... = ΞΌn
2.Β Β Β Β Β Β F ...
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