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ATQ,
First condition: N≡5(mod6). Let N=6a+5. Second condition: Quotient a≡3(mod4). Let a=4b+3. Substituting: N=6(4b+3)+5=24b+18+5=24b+23. Third condition: Quotient b≡3(mod4). Let b=4c+3. Substituting: N=24(4c+3)+23=96c+72+23=96c+95. Smallest N: Set c=0: N=96(0)+95=95. The least N is 95.
24% of 35% of (5/8) of 2400 = ?
3/7 Of 504 ÷ 12 + 17 = √?
(152 × 24 + 2540)/25 = 44464 ÷ ?
(6630 ÷ 13 + 6120 ÷ 12) ÷ (17 × 3) = ?
2(3/4) of 2880 + 54% of 7520 - ? = 302
(190/38) × (55/5) + (306/18) = ?
2916 ÷ 54 = ? + 27
132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
[(120)2 ÷24 ×25] ÷ 250 =?