Question

    What is least number which when successively divided by 6, 4 and 4 leaves a remainder 5, 3 and 3 respectively?

    A 191 Correct Answer Incorrect Answer
    B 177 Correct Answer Incorrect Answer
    C 57 Correct Answer Incorrect Answer
    D 17 Correct Answer Incorrect Answer

    Solution

    The Least number which when successively divided by 6, 4 and 4 leave remainders 5, 3 and 3 respectively. = [{(4 + 3) x 4} + 3] x 6 + 5 = 31 x 6 + 5 = 186 + 5 = 191

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