Question
A tiger chases deer. The deer is 175 leaps ahead of its
jumps from tiger. The Deer can jump 6 times in thetime in which the Tiger jumps 4 times. The distance covered by the deer and the tiger in one jump is 2.25m and 4.5m respectively. In how many jumps the tiger will catch the deer?Solution
Tiger’s 4 Jumps = Deer’s 6 Jump Speed – Tiger = 4 × 4.5 = 18m/s Speed – Deer = 6 × 2.25 = 13.5 m/s Extra Distance taken by Deer = 175 leaps of its jump Deer = (175 × 2.25) = 393.75 m Relative Speed = (18 – 13.5) =  4.5 m/s Time taken by Tiger to Chase Deer = 393.75/4.5 = 87.5 seconds Tiger has to jump to catch the Deer = 87.5 × 4 = 350 jumps.
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